Calculate the resultant force on a submerged plane surface and locate the center of pressure — for vertical, inclined, and horizontal surfaces.
Fluid Properties & StaticsVertical distance from the free surface to the centroid of the surface.
Measured from the horizontal. 90° = vertical surface, 0° = horizontal surface.
| Fluid | Water at 20°C, ρ = 998 kg/m³ |
| Gate shape | Rectangle, b = 1.5 m, H = 2 m |
| Inclination | 90° (vertical) |
| Depth to centroid | h̄ = 3 m (top edge at 2 m depth) |
Resultant hydrostatic force:
The magnitude equals the pressure at the centroid multiplied by the area. This is equivalent to integrating the pressure distribution over the surface.
Center of pressure (inclined surface, angle θ with horizontal):
The center of pressure is always below the centroid (hcp ≥ h̄) because pressure increases with depth. As depth increases (h̄ → ∞), e → 0 and C.P. approaches the centroid.
Second moments of area (centroidal, IG):
| Shape | Area A | IG |
|---|---|---|
| Rectangle | b × H | b H³ / 12 |
| Circle | π D² / 4 | π D⁴ / 64 |
| Triangle | ½ b H | b H³ / 36 |
IG is always about the centroidal axis parallel to the free surface(horizontal axis through the centroid). The parallel-axis theorem gives the second moment about the free-surface axis: Ix = IG + A ȳ².
Where: